What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N.
ANS= Round to 3 decimal places
Where do I begin?
safetyfactor=designload/load
now, you have to convert MPa to Newtons, to do that you have to have the crosssectional area.
tensiondesign=550 MPa*areainm^2
Sorry i missed this part of the question:
The steel hanger in question has a cross sectional area of 7.600cm^2
change that area to m^2, and solve.
Safety factor = design load/ load
= 550.000MPa = 550000000Pa
= 550000000/ 64000
= 8593.75
tension design = 550MPa * 0.076M^2
= 18.000
Have I messed thing up?
See your other post.
Try to work with stress for comparison.
To determine the factor of safety of a steel hanger, you need to divide its ultimate strength by the actual load it is supporting. Here are the steps to find the factor of safety:
Step 1: Define the given values:
- Ultimate strength of the steel hanger: 550,000 MPa
- Load supported by the hanger: 64,000 N
Step 2: Divide the ultimate strength by the load:
Factor of Safety = Ultimate Strength / Load
Step 3: Substitute the values into the formula:
Factor of Safety = 550,000 MPa / 64,000 N
Note: To divide units with different dimensions, you need to convert them to the same unit.
Step 4: Convert MPa to N:
1 MPa = 1 N/mm^2 (Newton per square millimeter)
So, we can convert MPa to N by multiplying 550,000 MPa by 1 N/mm^2, resulting in 550,000 N/mm^2.
Step 5: Convert N to N/mm^2:
1 N = 1 N/mm^2
Now, the load can be expressed as 64,000 N/mm^2.
Step 6: Plug in the converted values into the formula:
Factor of Safety = 550,000 N/mm^2 / 64,000 N/mm^2
Step 7: Simplify the expression:
Factor of Safety = 8.594
Step 8: Round the answer to three decimal places:
Factor of Safety = 8.594 (rounded to 3 decimal places)
Therefore, the factor of safety for the given steel hanger is approximately 8.594.