Please help me what is the ionic equation for AgNO3(aq) + Na3PO4(aq)?
Not sure what I'm doing wrong here is what I have so far 3Na^+(aq) + PO_4^-3(aq) + 3Ag^+(aq) +3NO^3-(aq) --> 3Na^+(aq) + 3NO^3-(aq) + Ag_3PO_4(s)
The full ionic equation looks ok. To make the net ionic equation cancel the 3NO3^- and 3Na^+ to become
3Ag^+(aq) + PO4^3-(aq) ==> Ag3PO4(s)
I think the nitrate ion is the problem here, too. Write it as NO3^-. It's the NO3 that has the 1- charge, not the NO that has the 3- charge.
You're on the right track, but it seems like you missed the charges on the ions. Let's break down the ionic equation step by step.
First, let's write the balanced molecular equation for the reaction:
AgNO3(aq) + Na3PO4(aq) -> Ag3PO4(s) + NaNO3(aq)
To write the ionic equation, we have to separate the reactants and products into their ionic forms, indicating their charges.
AgNO3(aq) dissociates into Ag+(aq) and NO3-(aq)
Na3PO4(aq) dissociates into 3Na+(aq) and PO4^3-(aq)
Ag3PO4(s) remains solid and does not dissociate into ions.
NaNO3(aq) dissociates into Na+(aq) and NO3-(aq)
Now, let's write the ionic equation using the dissociated ions:
Ag+(aq) + NO3-(aq) + 3Na+(aq) + PO4^3-(aq) -> Ag3PO4(s) + 3Na+(aq) + NO3-(aq)
Notice that Na+ and NO3- are present on both sides of the equation, so we can cancel them out. This leaves us with the simplified ionic equation:
Ag+(aq) + PO4^3-(aq) -> Ag3PO4(s)
Therefore, the ionic equation for the reaction is Ag+(aq) + PO4^3-(aq) -> Ag3PO4(s).