Take two glass put 20 g sugar in 20 ml water in first glass and put 15g sugar in 15 ml water in second glass now check out which one will be more concentrated and find out molarity normality of both
To find out which solution is more concentrated, we need to compare the molarities or normalities of both solutions. Let's begin by calculating the molarities of each solution.
First, let's calculate the molarity of the solution in the first glass.
Molarity (M) = Moles of solute / Volume of solution in liters
Given:
Mass of sugar in the first glass = 20 g
Volume of water in the first glass = 20 ml = 0.02 L
To find the moles of sugar, we need to convert grams to moles. The molar mass of sugar (sucrose) is 342.3 g/mol.
Moles of sugar in the first glass = Mass of sugar / Molar mass of sugar
= 20 g / 342.3 g/mol
Now, let's calculate the molarity of the solution in the first glass:
Molarity of the first solution = Moles of sugar / Volume of solution in liters
= Moles of sugar / 0.02 L
Repeat the same steps for the second glass:
Given:
Mass of sugar in the second glass = 15 g
Volume of water in the second glass = 15 ml = 0.015 L
Moles of sugar in the second glass = Mass of sugar / Molar mass of sugar
= 15 g / 342.3 g/mol
Molarity of the second solution = Moles of sugar / Volume of solution in liters
= Moles of sugar / 0.015 L
Now, let's calculate the normalities of both solutions.
Normality (N) = (Molarity in terms of moles) * (Number of equivalents)
Since sugar (sucrose) does not dissociate in water and does not produce ions, the normality will be the same as the molarity for both solutions.
Therefore, the molarity and normality of both solutions can be calculated using the steps mentioned above.