Take two glasses put 20g sugar in 2l water in first glass and put 15g sugar in 15ml water in second glass now Chekh out which one will be more concentrated and find out molarity normolity of both
To determine which solution is more concentrated and calculate their molarity (M) and normality (N), we need to understand the concepts of concentration and how to calculate them.
Concentration:
Concentration refers to the amount of solute (in this case, sugar) dissolved in a given amount of solvent (water). The concentration can be expressed in terms of molarity (M) or normality (N).
Molarity (M):
Molarity is the number of moles of solute dissolved per liter of solution. It is calculated using the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Normality (N):
Normality is the number of gram-equivalents of solute dissolved per liter of solution. It is calculated using the formula:
Normality (N) = (grams of solute) / (equivalent weight of solute) * (volume of solution in liters)
Now let's analyze the two scenarios:
First Glass:
Sugar = 20g
Water = 2 liters
To calculate the molarity (M), we need to know the molecular weight of sugar (sucrose). The molecular weight of sucrose is approximately 342.3 g/mol.
Molarity (M) = (20g / 342.3 g/mol) / 2L
Second Glass:
Sugar = 15g
Water = 15ml
To calculate the molarity (M), we need to first convert the volume to liters. 1 ml is equal to 0.001 liters.
Volume of solution in liters = 15 ml * 0.001 L/ml = 0.015 L
To calculate the normality (N), we need to know the equivalent weight of sugar (sucrose). The equivalent weight of sucrose is equal to its molecular weight divided by the number of hydrogen ions it can donate, which is 2.
Equivalent weight of sucrose = 342.3 g/mol / 2 = 171.15 g/equivalent
Normality (N) = (15g / 171.15 g/equivalent) * 0.015 L
Now, you can use these formulas to calculate the molarity and normality of both solutions individually.