The specific heat of aluminum is 0.214 cal/g·°C.
Calculate the heat necessary to raise the temperature of 47.9 g of aluminum from 18.9°C to 62.2°C
Heat (Q) evolved is Q = mc?T where m is the mass in grams, c is the specific heat and ?T is the change in temperature. In this case, the change in temperature is in degreesCelcius and the energy is in calories. You can do conversion in the final answer to joules if you want using;
1cal = 4.18joules.
hope that helps
To calculate the heat necessary to raise the temperature of aluminum, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat (in calories)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in cal/g·°C)
ΔT is the change in temperature (in °C)
In this case, the mass of aluminum (m) is 47.9 g, the specific heat capacity of aluminum (c) is 0.214 cal/g·°C, and the change in temperature (ΔT) is (62.2 - 18.9) °C = 43.3 °C.
Plugging these values into the formula, we get:
Q = 47.9 g * 0.214 cal/g·°C * 43.3 °C
Q = 452.5973 cal
Therefore, the heat necessary to raise the temperature of 47.9 g of aluminum from 18.9°C to 62.2°C is approximately 452.6 calories.