posted by Shadow .
The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8.
I use the change of base formula and got log6/log2 * log8/log6
log6/log2 * log2()^3/ log 6
I'm stuck here thanks.
you are correct in that you wind up with
log6/log2 * log8/log6
Now, you almost had it, since you recognized (I think) that 8 = 2^3. So, you have