Calculus
posted by Cole .
By recognizing each series below as a Taylor series evaluated at a particular value of x, find the sum of each convergent series.
A) 1+5 + (5^2)/(2!)+(5^3)/(3!)+(5^4)/(4!)+...+ (5^k)/(k!)+...=
B) 1(2^2)/(2!)+(2^4)/(4!)(2^6)/(6!)+...+((1)^(k)2^(2k))/((2k)!) +...=

e^x = 1+x+x^2/2! + ...
Looks like the series is e^5
Since cos(x) = 1  x^2/2! + ...
Looks like the series is cos(2)
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