Post a New Question


posted by .

A football is punted at an angle of 44.6 with the horizontal. if it stays in the air for 3.6 seconds, what was the initial velocity of the football?

  • Physics -

    The vertical component of the velocity is

    Vy = V cos 44.6 = .712V

    The height of the ball in feet is given by

    h(t) = (.712V)t - 16t^2
    So, if h(t) = 0 when t=3.6,

    .712V*3.6 - 16*3.6^2 = 0
    V = 80.9 ft/s

    Guy's a pretty decent kicker, since the average kickoff speed is about 50 mph = 73 ft/s

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question