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how do i calculate the point on the curve when the ordinate changes 8 times faster than abscissa in the equation 6y=x^3+2

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    the conditions mean that the slope is 8.

    y' is the slope, and since
    6y' = 3x^2
    y' = 1/2 x^2

    If 1/2 x^2 = 8, then x = 4

    So, at (4,11) the slope is 8

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    thank you

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