# BEST

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how do i calculate the point on the curve when the ordinate changes 8 times faster than abscissa in the equation 6y=x^3+2

• BEST -

the conditions mean that the slope is 8.

y' is the slope, and since
6y' = 3x^2
y' = 1/2 x^2

If 1/2 x^2 = 8, then x = 4

So, at (4,11) the slope is 8

• BEST -

thank you

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