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How many positive integers less than 1000000 have the sum of their digits equal to 7?
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792
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How many positive integers less than 1000000 have the sum of their digits equal to 7?
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Is the answer 920? i.e. (8+120+792)
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Find the sum of all positive integers m such that 2^m can be expressed as sums of four factorials (of positive integers).
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To find the sum of all positive integers m such that 2^m can be expressed as sums of four
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I am a number between 1000000 and 2000000. My ones digit is the sum of my tens and hundreds digits and is also the sum of my
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let the number be 1abcdef f=e+d f=1+b a=c a=f a+b+c+d+e+f+1=45 ok you have five equations and six
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Let S(n) denote the sum of digits of the integer n. Over all positive integers, the minimum and maximum values of S(n)/S(5n) are
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16
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the sum of the reciprocals of three consecutive positive integers is equal to 47 divided by the product of the integers. what is
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To solve this problem, let's assume that the three consecutive positive integers are x, x+1, and
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The sum of the reciprocals of three consecutive positive integers is equal to 47 divided by the product of the integers. What is
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Let's assume the three consecutive positive integers as x, x+1, and x+2. According to the given
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1.How many positive integers five-digit integers end with the digit 0? 9x10x10x10x? what number would represent zero
2.Using the
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1. To find the number of five-digit positive integers that end with the digit 0, you need to
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Find the sum of the first one thousand positive integers. Explain how you arrived at your result. Now explain how to find the
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the integers form an arithmetic sequence, with a = 1 d = 1 So, the sum of the 1st 1000 integers is
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Find how many positive integers with exactly four decimal digits, that is, positive integers between 1000 and 9999 inclusive,
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(a) div. by 5 and by 7 => div. by 35 We can find out that 35*286=10010 and 35*29=1015 Therefore the
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