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Consider the approximately normal population of heights of male college students with mean ì = 69 inches and standard deviation of ó = 4.6 inches. A random sample of 25 heights is obtained
(e) Find P(x > 70). (Give your answer correct to four decimal places.)


(f) Find P(x < 67). (Give your answer correct to four decimal places.)


Not sure how to work these?

  • math help -

    Does x = raw score or mean?

    If raw score:

    Z = (score-mean)/SD

    If mean:

    Z = (score-mean)/SEm

    SEm = SD/√n

    In both cases, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of Z.

  • math help -

    Find the reciprocal of the following number:

    -21/23

  • math check -

    -21/23=2.50=.9938 or is it 70-69=1over4.6/sqrt25=.92=.8212 for the first one
    the second part 67-69=-2over 4.6/sqrt25=.92, -2/.92=-2.17=.0150

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