Precalc
posted by Anonymous .
what is the inverse tangent of negative root3/3

let tan^1 (√3/3) = Ø
then tanØ = √3/3
I know tan 30° or tan π/6 = +√3/3
Ø must be in quadrants II or IV
in degrees: Ø = 18030=150° or Ø = 36030 = 330°
in radians: Ø = π  π/6 = 5π/6 or Ø = 2ππ/6 = 11π/6
notice that your calculator gives you 30° or π/6
which is correct since 30° is coterminal with 330°
calculators have been programmed to give the closest answer to zero, which in this case is 30°
the smallest positive answer is 5π/6