Physics 11th

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a body moves for a total of 9 seconds starting from rest with uniform acceleration and then with uniform retardation which is twice of value of acceleration to stop .what is the duration of uniform acceleration

  • Physics 11th -

    v=u+at

  • Physics 11th -

    Distance covered in 4 secods after tha 5th seconds= S9- s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n-1)

  • Physics 11th -

    Distance covered in 4 secods after tha 5th seconds= S9- s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n-1) The modern sr. sec. Bagpur palwal phone no. 8059892363

  • Physics 11th -

    Use v=u+at and form two equations one for acc. And one for retard. Then on solving u will get d ans. I hope dat helps.. 😀 ☺

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