0.63 gm of oxalic acid (COOH)2
2H20 are dissolved in 500 ml of solution. Calculate the molarity of the solution?
0.0161
molarity is the amount of solute dissolving in a liter of solute. H2O in the oxalic is simply water and so does not affect the molarity of the solution. The important part is the mass or mole of the pure oxalic acid.
so, find the actual mass of the pure oxalic acid. 0.63g is the mass for both the oxalic acid and water. You only need the oxalic acid mass.
then find the mole of pure oxalic acid from the mass you find. and finally, divide that mole with the volume in liters to get your molarity.
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To calculate the molarity of a solution, we need to use the formula:
Molarity (M) = (number of moles of solute) / (volume of solution in liters)
First, let's calculate the number of moles of oxalic acid (COOH)2 * 2H2O.
The molecular weight of oxalic acid (COOH)2 * 2H2O is:
(2 * 12.01 g/mol for carbon) + (4 * 16.00 g/mol for oxygen) + (2 * 1.01 g/mol for hydrogen) + (2 * 16.00 g/mol for water)
= 126.07 g/mol
Now, we can calculate the number of moles:
moles = mass / molecular weight
moles = 0.63 g / 126.07 g/mol
Next, we need to convert the volume of the solution from milliliters to liters:
volume = 500 ml = 500/1000 L
Finally, we can calculate the molarity:
Molarity = moles / volume
Molarity = (0.63 g / 126.07 g/mol) / (500/1000 L)
Now, let's calculate it.
Molarity = (0.63 g / 126.07 g/mol) / (500/1000 L)
Molarity = 0.005 mol / 0.5 L
Molarity = 0.01 M
Therefore, the molarity of the solution is 0.01 M.