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if the width of a rectangle is 5 inches shorter than the length and the perimeter of the rectangle is 80 inches.

how do you set up the equation for the perimeter involving only L and how do you solve this in a linear equation algebraically to find the length and the width

  • math -

    let the length be L
    "..the width of a rectangle is 5 inches shorter than the length"
    so width = L - 5

    Twice the width + twice the length = 80
    2L + 2(L-5) = 80

    take it from there.
    once you have L, evaluate L-5 for the width

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