Trigonometry..
posted by Lg .
During high tide the water depth in a harbour is 22 m and during low tide it is 10m(Assume a 12h cycle).
Calculate the times at which the water level is at 18m during the first 24 hours.
My solution:
first I found the cos equation: H(t)=6cos(π/6t)+16
then..
Let π/6t=Θ
18=6cosΘ+16
1816=6cosΘ
Θ=1.230959417
Then I don't know what's next....
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