Physics
posted by Isis .
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

I don't get what d0 means. Explain properly

Displacement with Constant Acceleration.This equation may be used to find the displacement of any object moving with constant acceleration. that's what it says

initial position d₀=0,
The maximum height at the motion with initial velocity v₀=20 m/s
is
H=v₀²/2g=20²/2•9.8 = 20.4 m (!!!)
H=v₀tgt²/2,
v(fin)= v₀ gt,
v(fin)=0, =>
0= v₀ gt =>
v₀ =gt,
H=gt²gt²/2= gt²/2,
t=sqrt{2H/g}=sqrt(2•20.4/9.8)=2.04 s