a 100 gram bullet is fired from a 10 kg gun with a speed of 1000m/sec. what is speed of recoil
Data:
m1=100gm=100/1000=0.10kg
m2=10kg
u1=0 m/s
u2=0 m/s
v1=1000 m/s
v2= ??
SOLUTION:
m1u1+m2u2=m1v1+m2v2
1*0+10*0=0.1*1000+10v2
0+0=100+10v2
-100=10v2
-100/10=v2
v2=-10m/s.
Answer
10m/s
M1v1=m2v2 farmula use hoga!
Briefly solved and 100%accurate👍
Well, the speed of recoil can be calculated using Newton's third law of motion: for every action, there is an equal and opposite reaction. So, let's do some math!
Let's assume there is no external force acting on the gun and bullet system. The mass of the bullet is 100 grams, which is 0.1 kg, and the mass of the gun is 10 kg. The initial velocity of the bullet is 1000 m/s.
Using the conservation of momentum principle, we can say that the momentum of the bullet before firing is equal to the momentum of the combined system after firing. The equation can be written as:
(mass of bullet * velocity of bullet) + (mass of gun * velocity of gun) = 0
(0.1 kg * 1000 m/s) + (10 kg * velocity of gun) = 0
10 kg * velocity of gun = -0.1 kg * 1000 m/s
velocity of gun = -0.1 kg * 1000 m/s / 10 kg
velocity of gun = -1 m/s
Interestingly, the answer is -1 m/s. The negative sign indicates that the gun recoils in the opposite direction of the bullet's motion, which means it moves backward at a speed of 1 m/s.
So, the speed of recoil of the gun is 1 m/s. I hope this answer doesn't make you recoil in horror!
To find the speed of the recoil, we can use the principle of conservation of momentum. According to this principle, the total momentum before and after an event remains constant, assuming there are no external forces acting on the system.
In this scenario, the bullet and the gun are considered as a system, and their initial momentum is zero since they are at rest. After the bullet is fired, the system gains momentum in the forward direction due to the bullet, while the gun experiences an equal and opposite momentum in the backward direction.
The equation for momentum is:
Momentum = mass * velocity
Before firing the bullet:
Total initial momentum = (mass of bullet + mass of gun) * 0
After firing the bullet:
Total final momentum = mass of bullet * velocity of bullet + mass of gun * velocity of gun
Since the initial momentum is zero, we can set the total final momentum equal to zero as well:
0 = (mass of bullet * velocity of bullet) + (mass of gun * velocity of gun)
Now, let's substitute the given values into the equation:
0 = (0.1 kg * 1000 m/s) + (10 kg * velocity of gun)
Simplifying the equation:
0 = 100 kg m/s + 10 kg * velocity of gun
-100 kg m/s = 10 kg * velocity of gun
Dividing both sides of the equation by 10 kg:
-10 m/s = velocity of gun
Therefore, the speed of the recoil is 10 m/s in the opposite direction of the bullet.