posted by kitor
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
s2(g)+C(s)-->CS2(g) Kc=9.40 at 900k
How many grams of CS2(g) can be prepared by heating 14.5 moles of S2(g) with excess carbon in a 8.15 L reaction vessel held at 900 K until equilibrium is attained?