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a train starts from rest and accelerates unifotmly, until it has travled 3.7 km and acquired a velocity of 30 m/s. the train then moves at a constant velocity of 30 m/s for 410 s. the train then slows down uniformly at 0.065 m/s^2, until it reaches a halt. what distance does the train travel while it is slowing down

  • physics -

    V^2 = Vo^2 + 2ad
    a=(V^2-Vo^2)/2d=(900-0)/7400=0.122 m/s^2

    d2 = 30m/s * 410s = 12300 m.

    d3 = (V^2-Vo^2)/2a
    d3 = (0-900)/-0.130 = 6923 m.

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