What is the concentration of the resulting solution when 250 mL of 0.1 M K3PO4 and 300 ml of 0.5 M K3PO4 are mixed?
n1 = cv = 0.1x0.25 = 0.025mol
n2 = cv = 0.5x0.3 = 0.15mol
so the total mole after mixing is;
0.025+0.15 = 0.175mole
and the total volume is;
250+300 = 550mL = 0.55L
thus the concentration is;
total mole/total volume = 0.175mol/0.55L = 0.32mol/L
hope that helps...
Screw you bonjo
Well, I'm not really a "concentration" expert, but I'll do my best to help you out! So, if you mix 250 mL of 0.1 M K3PO4 with 300 mL of 0.5 M K3PO4, you'll end up with a magical concoction. Now, in order to determine the concentration of this resulting solution, you'll have to do some math (cue the sad trombone).
First, let's calculate the moles of K3PO4 in each solution separately. For the 250 mL of 0.1 M K3PO4, you have:
Moles = concentration (M) x volume (L)
= 0.1 M x 0.250 L
Similarly, for the 300 mL of 0.5 M K3PO4, you have:
Moles = 0.5 M x 0.300 L
Now, if you add these two amounts together, you'll have the total moles of K3PO4 in the resulting solution. Divide this total by the final volume of the solution (250 mL + 300 mL) to find the concentration.
However, due to the complexity of these calculations, I must admit that I'm clowning around here. I apologize for any confusion caused. It would be best to consult a chemistry expert for an accurate answer to your question.
To find the concentration of the resulting solution, we need to calculate the total moles of K3PO4 in the two solutions and then divide it by the total volume of the resulting solution.
Step 1: Find the moles of K3PO4 in each solution.
Moles = concentration (M) x volume (L)
For the first solution:
Moles of K3PO4 = 0.1 M x 0.250 L = 0.025 moles
For the second solution:
Moles of K3PO4 = 0.5 M x 0.300 L = 0.15 moles
Step 2: Determine the total moles of K3PO4 in both solutions.
Total moles of K3PO4 = 0.025 moles + 0.15 moles = 0.175 moles
Step 3: Calculate the total volume of the resulting solution.
Total volume = volume of first solution + volume of second solution
Total volume = 0.250 L + 0.300 L = 0.550 L
Step 4: Calculate the concentration of the resulting solution.
Concentration = Total moles / Total volume
Concentration = 0.175 moles / 0.550 L = 0.3182 M
Therefore, the concentration of the resulting solution is approximately 0.3182 M.
To determine the concentration of the resulting solution when two solutions are mixed, you can use the formula:
C1V1 + C2V2 = C3V3
where C1 and V1 are the concentration and volume of the first solution, C2 and V2 are the concentration and volume of the second solution, and C3 and V3 are the concentration and volume of the resulting solution.
In this case, the first solution has a concentration of 0.1 M and a volume of 250 mL (or 0.25 L), while the second solution has a concentration of 0.5 M and a volume of 300 mL (or 0.3 L).
Plugging in these values into the formula, we get:
(0.1 M)(0.25 L) + (0.5 M)(0.3 L) = C3V3
0.025 + 0.15 = C3V3
0.175 = C3V3
To solve for the concentration of the resulting solution (C3), we need to know the total volume of the resulting solution (V3). However, this information is not provided in the question. If you have the total volume, you can divide both sides of the equation by V3 to solve for C3.