What is the product of (3x+2) and (x-7)?
I got 3xsquared-23x-14. Is this correct?
Almost right
(3x+2) (x-7)
3x^2 -21x + 2x -14
3x^2 -19x -14
Thank you!
To find the product of (3x + 2) and (x - 7), you need to use the distributive property.
Multiply the first term of the first polynomial (3x) by each term in the second polynomial (x and -7):
(3x)(x) = 3x^2
(3x)(-7) = -21x
Next, multiply the second term of the first polynomial (2) by each term in the second polynomial (x and -7):
(2)(x) = 2x
(2)(-7) = -14
Now, combine like terms:
3x^2 - 21x + 2x - 14
Simplifying further:
3x^2 - 19x - 14
So, the correct answer is 3x^2 - 19x - 14.
To find the product of (3x + 2) and (x - 7), you need to use the distributive property. This property states that when you multiply two expressions, each term in the first expression needs to be multiplied by each term in the second expression.
First, multiply the terms in the first expression (3x + 2) by the first term in the second expression (x):
(3x) * (x) = 3x^2
Next, multiply the terms in the first expression (3x + 2) by the second term in the second expression (-7):
(3x) * (-7) = -21x
Now, multiply the terms in the first expression (2) by the first term in the second expression (x):
(2) * (x) = 2x
Finally, multiply the terms in the first expression (2) by the second term in the second expression (-7):
(2) * (-7) = -14
Now, combine all the results:
3x^2 - 21x + 2x - 14
Simplifying the expression further:
3x^2 - 19x - 14
So, the correct product of (3x + 2) and (x - 7) is 3x^2 - 19x - 14. Therefore, your equation is incorrect.