Math Trig Find Quadrant I II III IV
posted by Hello .
In which quadrant is the terminal side of angle A?
A = 5π/6
a. Quadrant III
b. Quadrant I
c. Quadrant II
d. Quadrant IV

Think of degrees if radians give you trouble
π radians = 180°
so (5/6)π radians = (5/6)(180)° = 150°
so going clockwise 150° would put you into quadrant III 
Hello, i cant find out the values of x1,x2 can u help me please?
sinx=2sinx+1
0=sinx+1
sinx=1 <0 (III;IV)
sinx=270*
x1= ?
x2= ? 
to Fred:
sinx=2sinx+1
0=2sinx+1sinx
0=sinx+1
sinx=1
We are going to look for the values of x.
sin is < 0 meaning, the values are either in quadrant III/ IV.
First, identify the rad equivalent where sin equates to 1.
And that would be 270 degrees or 3pi/2 located at the 3rd quadrant.
3rd quadrant (check!)
4th quadrant (?)
The range for the 3rd quadrant is 180270 degrees, and the range of for 4th quadrant is from 270360 degrees.
if you have a limit such as the values are only within [0, 2pi] then you only need 3pi/2 since its within the 3rd and 4th quadrant.
x1= 3pi/2. x2= 3pi/2. 
In which quadrant does the terminal side of a 240° angle in standard position lie?
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