In which quadrant is the terminal side of angle A?

A = -5π/6

a. Quadrant III
b. Quadrant I
c. Quadrant II
d. Quadrant IV

Think of degrees if radians give you trouble

π radians = 180°
so (-5/6)π radians = -(5/6)(180)° = -150°
so going clockwise 150° would put you into quadrant III

Hello, i cant find out the values of x1,x2 can u help me please?

sinx=2sinx+1
0=sinx+1
sinx=-1 <0 (III;IV)
sinx=270*

x1= ?
x2= ?

to Fred:

sinx=2sinx+1
0=2sinx+1-sinx
0=sinx+1
sinx=-1

We are going to look for the values of x.
sin is < 0 meaning, the values are either in quadrant III/ IV.
First, identify the rad equivalent where sin equates to -1.

And that would be 270 degrees or 3pi/2 located at the 3rd quadrant.
3rd quadrant (check!)
4th quadrant (?)

The range for the 3rd quadrant is 180-270 degrees, and the range of for 4th quadrant is from 270-360 degrees.

if you have a limit such as the values are only within [0, 2pi] then you only need 3pi/2 since its within the 3rd and 4th quadrant.

x1= 3pi/2. x2= 3pi/2.

In which quadrant does the terminal side of a 240° angle in standard position lie?

To determine which quadrant the terminal side of angle A is in, we need to understand the unit circle and the values of sine and cosine in each quadrant.

The unit circle is a circle with a radius of 1, centered at the origin of a coordinate plane. It is divided into four quadrants, labeled as follows:
- Quadrant I: The top right quadrant, where both the x and y coordinates are positive.
- Quadrant II: The top left quadrant, where the x coordinate is negative and the y coordinate is positive.
- Quadrant III: The bottom left quadrant, where both the x and y coordinates are negative.
- Quadrant IV: The bottom right quadrant, where the x coordinate is positive and the y coordinate is negative.

Angle A = -5π/6 is negative and lies in Quadrant III.

To visualize this, you can start from the positive x-axis, rotate anti-clockwise by an angle of 5π/6 (which is greater than π radians or 180 degrees), and you'll end up in Quadrant III.

Therefore, the answer is: Quadrant III. (a. Quadrant III)