math check
posted by Nora 56 .
Posted by Nora 56 on Sunday, June 2, 2013 at 7:32pm.
Sorry to repost but no one answered after I posted on the 2nd,please help,
Suppose that you are in a class of 31 students and it is assumed that approximately 13% of the population is lefthanded. (Give your answers correct to three decimal places.)
(a) Compute the probability that exactly five students are lefthanded.
Answer .161
(b) Compute the probability that at most four students are lefthanded.
Answer .129
(c) Compute the probability that at least six students are lefthanded.
Answer .193
•Math check answer  bobpursley, Sunday, June 2, 2013 at 8:19pm
a. what is .13^5 * .87^(315) >
Put .13^5 * .87^(315)= in your google search window.
b. at most four students...
add the probabliliy of one, two, three, four, and none are left handed.
Pr=.13^0*.87^31+.13^1*.87^30 + ...
c. at least six?
that is the same as 1 probability5orless
= 1 Pr(a)Pr (b) where pr(a), pr(b) is in part a, and b.
•Math check answer  Nora 56, Thursday, June 6, 2013 at 10:01am
I worked this out like you said above and got (a)9.936 (b)9.955 and both of them were wrong, any suggestions????
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