a bowling ball with a mass of 10 kg and a bowling pin with a mass of 0.5kg, are standing 2m apart, from centre to centre. what is the force of attraction between the bowling ball and the pin

To calculate the force of attraction between the bowling ball and the pin, you need to apply Newton's law of universal gravitation. This law states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

The equation is F = (G * m1 * m2) / r^2,

Where:
- F is the force of attraction between the objects
- G is the gravitational constant (approximately 6.67430 × 10^-11 N m^2/kg^2)
- m1 and m2 are the masses of the objects
- r is the distance between their centers

In this case, the bowling ball has a mass of 10 kg (m1) and the bowling pin has a mass of 0.5 kg (m2). The distance between their centers is given as 2 meters (r).

Plugging in the values, the equation becomes:
F = (6.67430 × 10^-11 N m^2/kg^2 * 10 kg * 0.5 kg) / (2 m)^2

Now, we can solve for the force of attraction:
F = (6.67430 × 10^-11 N m^2/kg^2 * 5 kg) / 4 m^2

F = (3.33715 × 10^-10 N m^2/kg) / 4 m^2

F = 8.34288 × 10^-11 N

Therefore, the force of attraction between the bowling ball and the pin is approximately 8.34288 × 10^-11 Newtons.