two cars weighing 1500 kg are made to collide with a wall.the initial and final velocities are 15 m/s and 2.6 m/s.if the collision last for 0.15 seconds,then find impulsive force exerted on the car
This makes no sense.
agreed....do you mean the two cars collided elastically with each other?
To find the impulsive force exerted on the car, we need to use the principle of conservation of momentum.
The principle of conservation of momentum states that the total momentum before a collision is equal to the total momentum after the collision, as long as no external forces are acting on the system.
The formula to calculate momentum is:
Momentum = mass x velocity
Given:
Mass of each car (m1 and m2) = 1500 kg
Initial velocity of car 1 (u1) = 15 m/s
Initial velocity of car 2 (u2) = 0 m/s (as it's colliding with a wall)
Final velocity of car 1 (v1) = 2.6 m/s
Final velocity of car 2 (v2) = 0 m/s (as it collides with a wall)
Time (t) = 0.15 seconds
Step 1: Calculate the momentum before the collision:
Momentum before the collision = (m1 x u1) + (m2 x u2)
Momentum before the collision = (1500 kg x 15 m/s) + (1500 kg x 0 m/s)
Momentum before the collision = 22500 kg.m/s
Step 2: Calculate the momentum after the collision:
Momentum after the collision = (m1 x v1) + (m2 x v2)
Momentum after the collision = (1500 kg x 2.6 m/s) + (1500 kg x 0 m/s)
Momentum after the collision = 3900 kg.m/s
Step 3: Calculate the change in momentum:
Change in momentum = Momentum after the collision - Momentum before the collision
Change in momentum = 3900 kg.m/s - 22500 kg.m/s
Change in momentum = -18600 kg.m/s
Step 4: Calculate the impulsive force:
Impulsive force = Change in momentum / time
Impulsive force = -18600 kg.m/s / 0.15 s
Impulsive force ≈ -124000 N (Note: The negative sign indicates that the force is exerted in the opposite direction)
Therefore, the impulsive force exerted on the car is approximately 124,000 Newtons in the opposite direction.