# Math for Educators

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Find the 9th term of sequence.

4, 12, 36, 108, ....

The 9th term of sequence is ??

4+[3(n-1)]

Correct?

• Math for Educators -

Looks like Tn = 4*3^(n-1)
So, T9 = 4*3^8 = 26244

4,12,36,108,324,972,2916,8748,26244,...

With your proposed sequence 4+3(n-1) how did you get such a large number?

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