1. If square root of 3x-11 +10 = 17, find the value of 10 x .
I don't know how to solve with square roots.
I subtracted 10 from both sides, so I'm left with square root of 3x-11 = 7...How do I solve for x?
If x- 4/x+3 = x+3, Find the value of -2x.
When I solved for x I got x = -3, so -2x would be 6. Did I do this correctly?
And I just tried to solve the first problem. So if I square both sides, it would be 3x-11 = 49, so x = 20?
(10x would be 200)
for the 1st one, does x=20 satisfy the original equation? Yes. √(60-11) + 10 = 17
For the 2nd, does x=-3 work? No, because then x+3=0 and you can't divide by 0.
(x-4)/(x+3) = x+3
x-4 = (x+3)^2
x-4 = x^2+6x+9
x^2+5x+13 = 0
No real solutions
If you meant
x - 4/(x+3) = x+3
then
x(x+3) - 4 = (x+3)^2
x^2+3x-4 = x^2+6x+9
3x = -13
x = -13/3
How did you get x = -3?
Short answer to your question: No
Rather than come here and ask whether your answers are correct, plug them into the original equation and see whether they work. If so, you probably did it right. If not, then pop in here and show your work, and we can steer you straight.
To solve for x in the equation √(3x-11) + 10 = 17, follow these steps:
Step 1: Start by subtracting 10 from both sides of the equation:
√(3x-11) = 17 - 10
√(3x-11) = 7
Step 2: Square both sides of the equation to eliminate the square root:
(√(3x-11))^2 = 7^2
3x-11 = 49
Step 3: Add 11 to both sides of the equation:
3x = 49 + 11
3x = 60
Step 4: Divide both sides of the equation by 3:
x = 60/3
x = 20
Step 5: Finally, multiply x by 10 to find the value of 10x:
10x = 10 * 20
10x = 200
Therefore, the value of 10x is 200.