Consider the following.
P(A) = 0.27 and P(B) = 0.36,
A and B are mutually exclusive events
(a) Find the probability P(A). (Give your answer correct to two decimal places.)
(b) Find the probability P(B). (Give your answer correct to two decimal places.)
(c) Find the probability P(A or B). (Give your answer correct to two decimal places.)
(d) Find the probability P(A and B). (Give your answer correct to two decimal places.)
A. I put 0.27
b. 0.36
c. 0.56 because I multiplied them both together.
d. I put 0.56 also but that was wrong?????
I got the whole thing wrong
Hints:
P(A∪B)=P(A)+P(B)-P(A∩B)
If A and B are mutually exclusive (ME), then P(A∩B)=0.
This should take care of (d)
To find the probability values in this scenario, we can use the given information and apply the rules of probability.
(a) To find the probability P(A), we are given that P(A) = 0.27, which means that the probability of event A occurring is 0.27.
(b) To find the probability P(B), we are given that P(B) = 0.36, which means that the probability of event B occurring is 0.36.
(c) To find the probability P(A or B) of event A or event B occurring, we can use the formula:
P(A or B) = P(A) + P(B)
Since A and B are mutually exclusive events, this means that they cannot occur at the same time. Therefore, the probability of either A or B occurring is simply the sum of their individual probabilities:
P(A or B) = P(A) + P(B) = 0.27 + 0.36 = 0.63
So, the probability of event A or event B occurring is 0.63.
(d) To find the probability P(A and B) of event A and event B occurring, we know that mutually exclusive events cannot occur at the same time. Therefore, the probability of event A and event B occurring together is 0.
P(A and B) = 0
So, the probability of event A and event B occurring together is 0.
In summary:
(a) P(A) = 0.27
(b) P(B) = 0.36
(c) P(A or B) = 0.63
(d) P(A and B) = 0