How much work does it take to stretch a spring with k= 150N/M 10cm from equilibrium?
.75 Joules
To calculate the work required to stretch a spring, we can use the formula:
Work (W) = (1/2)kx^2
where:
W is the work done,
k is the spring constant, and
x is the displacement from equilibrium.
Given:
k = 150 N/m (spring constant),
x = 10 cm = 0.1 m (displacement).
Substituting these values into the formula:
W = (1/2)(150 N/m)(0.1 m)^2
W = (1/2)(150 N/m)(0.01 m^2)
W = 0.5(150 N/m)(0.01 m^2)
W = 0.5(1.5 N)
W = 0.75 N
Therefore, it takes approximately 0.75 Joules of work to stretch the spring 10 cm from equilibrium.
To find out how much work is required to stretch a spring a certain distance, we can use the formula for work done by a spring:
Work = (1/2) * k * x^2
where k is the spring constant and x is the displacement from equilibrium.
Given that k = 150 N/m and x = 10 cm = 0.1 m, we can plug these values into the formula:
Work = (1/2) * 150 N/m * (0.1 m)^2
= (1/2) * 150 N/m * 0.01 m^2
= 0.75 N*m
Therefore, it takes 0.75 joules of work to stretch the spring 10 cm from equilibrium.