2. How many oxygen atoms are indicated on the right side
of this balanced chemical equation?
4 Cr(s) + 3 O2( g)h2 Cr2O3( g)
What you have written in not a balanced chemical reaction.
Where is the arrow (->) ?
An arrow must separate the two sides of the reaction.
What is h2?
Cr2O3 is not a gas
To determine the number of oxygen atoms on the right side of the balanced chemical equation, you need to examine the coefficients in front of the oxygen-containing molecules. In this case, the balanced equation is:
4 Cr(s) + 3 O2(g) → 2 Cr2O3(g)
Looking at the right side of the equation, you can see that there are two Cr2O3 molecules. Each Cr2O3 molecule consists of two chromium (Cr) atoms and three oxygen (O) atoms. Therefore, the total number of oxygen atoms on the right side is:
2 Cr2O3 x 3 O atoms = 6 O atoms
So, there are six oxygen atoms indicated on the right side of the balanced chemical equation.