Yikes! Help please.
In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 16 consonants, what is the probability you will choose a consonant and then a vowel?
options:
1/44, 56/11, 28/121, 112/11
To find the probability of choosing a consonant and then a vowel, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's find the total number of possible outcomes. Since you replace the tile after each selection, the total number of possibilities for the first selection is equal to the total number of tiles in the bag. In this case, there are 28 vowels + 16 consonants = 44 total tiles.
After the first selection, since you replace the tile, the total number of possibilities for the second selection is also 44.
Now, let's find the number of favorable outcomes, which is selecting a consonant and then a vowel. The number of possibilities for the first selection is 16 consonants, and the number of possibilities for the second selection is 28 vowels.
Now, let's calculate the probability using the formula:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = (16/44) * (28/44) = 448/1936 = 112/484 = 28/121
Therefore, the probability of choosing a consonant and then a vowel is 28/121.
So, the correct option is: 28/121.
Since there are 44 tiles total, that would be
16/44 * 28/44 = 28/121