find indefinite integral [(sinx)^3]*[(cosx)^3] dx
i got 1/192 * ((cos(6x)-9cos(2x)) + C
but this isnt right. explain plz? thnx
You may want to show your work to know how you got your answer.
The good news is that your indefinite integral is correct, but off by 1/24, which can be absorbed in the integration constant.
Depending on how you integrated, it could give equivalent results of:
(3sin(x)^4-2sin(x)^6)/12, or
(2cos(x)^6-3cos(x)^4)/12
The latter is your answer less 1/24, the constant.