what volume of water is required to make 0.20 M solution from 16 ml of 0.5 M solution?
Answer is 24ml as 40ml must be the volume of solution and volume of solute is already given as 16ml.
Sorry that wasn't volume of solute, the question is asking of the water required and so answer is 24ml.
To find out the volume of water required, we need to use the formula for dilution:
(Concentration)(Volume) = (Concentration)(Volume)
Let's plug in the values we have:
(0.5 M)(16 mL) = (0.20 M)(Volume of water + 16 mL)
Now, let's solve for the unknown, which is the volume of water.
0.5 M * 16 mL = 0.20 M * (Volume of water + 16 mL)
8 mL = 0.20 M * Volume of water + 3.2 mL
Subtracting 3.2 mL from both sides:
8 mL - 3.2 mL = 0.20 M * Volume of water
4.8 mL = 0.20 M * Volume of water
Now, divide both sides by 0.20 M to solve for the volume of water:
4.8 mL / 0.20 M = Volume of water
Volume of water = 24 mL
Therefore, you would need to add 24 mL of water to the 16 mL of the 0.5 M solution to make a 0.20 M solution.
I have not achieve my answer can u explain
mL1 x M1 = mL2 x M2
16 mL x 0.5M = mL2 x 0.20M