Calculate the volume occupied by 200g of steam at 200 °C and 0.5 atm.
is my answer correct:
PV = nRT
V = nRT/P
V = gRT/mm P
V = (200g H2O)(0.0821 liters atm/1mole K)(473 K)/ (18g H2O/1mole )(0.5 liters atm) = 863 liters
I agree
To calculate the volume occupied by 200g of steam at 200 °C and 0.5 atm, you used the ideal gas law equation: PV = nRT. However, steam is not an ideal gas, so using this equation directly may not provide an accurate result.
To get a more accurate value for the volume, you can use an equation specific to steam called the steam table. Steam tables provide information on the properties of water and steam at different temperatures and pressures.
To use the steam table, you need to have the saturation pressure at the given temperature (200 °C) and then compare it to the given pressure (0.5 atm) to determine whether the steam is saturated or superheated.
Assuming the steam is saturated, you can find the corresponding specific volume (volume per unit mass) from the steam table. Let's assume the specific volume is v = 0.3 m³/kg.
To find the volume occupied by 200g of steam, you can convert the mass to kg and multiply it by the specific volume:
m = 200g = 0.2kg
V = m * v = 0.2kg * 0.3 m³/kg = 0.06 m³
Therefore, the volume occupied by 200g of steam at 200 °C and 0.5 atm is approximately 0.06 m³.