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Calculate the volume occupied by 200g of steam at 200 °C and 0.5 atm.

is my answer correct:

PV = nRT
V = nRT/P
V = gRT/mm P

V = (200g H2O)(0.0821 liters atm/1mole K)(473 K)/ (18g H2O/1mole )(0.5 liters atm) = 863 liters

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    I agree

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