Post a New Question

Indefinite Integrals

posted by .

find the indefinite integral of

(1/x)*(e^(-2log[ 3,x])) dx

where 3 is base of the log

i cannot even figure out where to start :( please help. thank you

  • Indefinite Integrals -

    log_3(x) = lnx/ln3

    = e^(-2lnx/ln3)
    = (e^(lnx))^(-2/ln3)
    = x^(-2/ln3)

    so you have
    ∫(1/x) x^(-2/ln3) dx
    = ∫x^(-2/ln3-1) dx
    = 1/(-2/ln3) x^(-2/ln3)
    -ln3/2 x^(-2/ln3)

  • Bridesmaid Dresses: Spring/Summer 2014 Styles From -

    <strong>Bridesmaid Dresses: Spring/Summer 2014 Styles From Top Designers (PHOTOS)</strong></br>

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question