Integrals- Log/Ln

posted by .

Can you check this please

i'm not sure why it's wrong .__.

1) indefinite integral of 1/t *ln(t) dt
the t*ln(t) is altogether on the bottom
i got ln(ln(x)) + C

2) find the indefinite integral of 1/(sqrt(t)*[1-2*sqrt(t)]dt
sqrt(x) is on the bottom.
i got -ln(1-2*sqrt(t))+C

can you tell me why mine's answers are wrong? thnx

  • Integrals- Log/Ln -

    1. u = ln(t)
    du = 1/t dt
    u du
    u^2/2 + c

    (ln(2))^2/2 + c

    2. 1/t^2 (1- 2t^2)dt
    Then multiply 1/t^2
    (1/t^2 -2)dt
    -1/t -2t + c

  • Integrals- Log/Ln -

    Typo
    (ln(t))^2/2 + c

  • Integrals- Log/Ln -

    I'm still getting it wrong, so I'm not sure what's with that.. Thank you for your help though!

  • Integrals- Log/Ln -

    #1 is correct: ln(lnx))+C

    #2: If you mean
    ∫ 1/√t * (1-2√t) dt
    Let u = 1-2√t
    du = -1/√t dt
    and you have
    ∫-u du
    = -1/2 u^2 + C
    = -1/2 (1-2√t)^2 + C
    = -1/2 (1 - 4√t + 4t) + C
    = -2 + 2√t - 2t + C
    you can absorb the -2 into C, leaving
    2√t - 2t + C

  • Integrals- Log/Ln -

    Or, if you mean
    ∫ 1/(√t * (1-2√t)) dt
    Again let u=1-2√t
    du = -1/√t dt
    and we have

    ∫ -1/u du
    = -lnu + C
    = -ln(1-2√t) + C

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. CALCULUS 2!!! PLEASE HELP!!

    I'm having trouble with this question on arc length: y=lnx, (squareroot)3/3 greater than or equal to x less than or equal to 1 It sounds as if you want the length of the y = ln x curve from x = sqrt(3)/3 (0.57735..) to 1. The formula …
  2. Calculus

    Solve these indefinite and definite integrals. [integration sign] 4j-5j^3 dj I got 2j^2 - 5/4j^4... is this my final answer?
  3. Calculus

    Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of (sin(3*pi*t))dt For this one, I got -1/3pi cos (9 pi^2) + 1/3pi 2. indefinite integral of sinxcos(cosx)dx I got sin(cosx) + C 3. Indefinite integral of x over (root …
  4. Math

    I need help with this partial fraction problem. Find the indefinite integral of (-5x^3+5x^2-5)/(x^4+X^3). I got -5(log(x+1)+(1/x)-(1/(2x^2)).
  5. Maths

    What is the answer for these questions:- 1) Indefinite Integrals gcx) = (8 + 39x ^ 3) / x 2) Indefinite Integrals hcu) = sin ^2 (1/8 u) 3) Evaluate x ( 8 - 5 x ^2) dx Thank you
  6. Calc BC

    1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2(pix/7)dx 2. Find the indefinite integral by making the substitution x=3tan(theta). Indefinite integral x*sqrt(9+x^2)dx 3. Find the indefinite integral. Indefinite …
  7. Indefinite Integrals

    find the indefinite integral of (1/x)*(e^(-2log[ 3,x])) dx where 3 is base of the log i cannot even figure out where to start :( please help. thank you
  8. Math

    good day please help with this indefinite integral,especially what formula i can use to solve it-2x+1/(3x^2+3x+5)dx.Find the indefinite integral.
  9. Calculus indefinite integrals

    Evaluate the following indefinite integrals using substitution a) ∫ xsqrt(x^2-7) dx b) ∫ x^(2/3)(1/5x^(5/3)+2)^4 dx
  10. Math (Integrals)

    Find the indefinite integral in two ways. ∫(2x-1)^2 dx The first way I used was using the power rule and chain rule with substitution. Let u = 2x - 1 du = 2 dx (1/2)∫ u^2 du (Applying power rule) (1/2) * (u^3/3) + C =(2x-1)^3/6 …

More Similar Questions