a particle moving with a acceleration travels 24m and 64m in the first two consecutive intervals of 4 seconds each.find its initial velocity

To find the initial velocity of the particle, we can use the equation of motion:

v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

In this case, we are given the values of displacement (s) and time (t) for the first two intervals. Let's calculate the average velocity for each interval, and then we can find the final velocity for the second interval:

For the first interval (t = 4 seconds):
s1 = 24m
t1 = 4s

Average velocity for the first interval:
v1 = s1 / t1

For the second interval (t = 4 seconds):
s2 = 64m
t2 = 4s

Average velocity for the second interval:
v2 = s2 / t2

Since the final velocity after the first interval is the initial velocity for the second interval (u = v1), we can substitute this value into the equation of motion for the second interval:

v2 = u + at2

Now, let's solve for u (initial velocity):

u = v2 - at2

Substituting the values we calculated:
u = v2 - a(4)

Finally, we can find the initial velocity u by plugging in the average velocity (v2) and the given acceleration:

u = v2 - a(4)

Please provide the value of acceleration (a) in order to calculate the initial velocity.