LIMITS
posted by help pls .
lim [cotx  (1/x)]
x>0

cotx  1/x = (xtanx)/(x tanx)
now apply L'Hospital's Rule, so the limit is also
(1sec^2 x)/(tanx  xsec^2 x)
and again
2sec^2 x tanx / (sec^2 x  2sec^2 x tanx)
= 2sec^2x tanx / (sec^2x(12tanx))
= 0/1
so the limit is 0
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