PHYSICS FINAL (orbital)
posted by Mike Jones .
A 3300kg satellite is traveling 3550 km above the Earth's surface. Calculate the velocity and period of the satellite.
THANK YOU VERY MUCH!!!!

The satellite's mass doesn't matter.
You will need to use the fact that the Earth's radius is 6371 km. The satellite is therefore 9921 km from the Earth's center. The value of the acceleration of gravity (g') there is
g' = g*(6371/9921)^2 = 4.046 m/s^2
where g = 9.81 m/s^2 is the value of the acceleration at the Earth's surface.
You can get the velocity V by using
V^2/R = g'
V = 6335 m/s
The period P of the satellite is given by
V*P = 2*pi*R
P = 9840 s = 2.73 hours
Respond to this Question
Similar Questions

PHYSICS SATELLITE PROBLEM
A 3300kg satellite is traveling 3550 km above the Earth's surface. Calculate the velocity and period of the satellite. THANK YOU VERY MUCH!!!! 
PLEASE HELP FINAL PROBLEM ORBITAL
A 3300kg satellite is traveling 3550 km above the Earth's surface. Calculate the velocity and period of the satellite. THANK YOU VERY MUCH!!!! 
physics
A geosynchronous Earth satellite is one that has an orbital period equal to the rotational period of the Earth. Such orbits are useful for communication and weather observation because the satellite remains above the same point on … 
physics
A satellite of mass 205 kg is launched from a site on Earth's equator into an orbit at 200 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite? 
physics
NASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. The mass of the satellite is 550 kg. (Assume the Earth's mass is 5.97 1024 kg and its radius is 6.38 106 m.) (a) How … 
physics
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 427 km above the earthâ€™s surface, while that for satellite B is at a height of 873 km. Find the orbital speed for (a) satellite A … 
astronomy
A geosynchronous satellite is a satellite whose orbital period matches the rotation of the Earth. Calculate the height above the surface of the Earth which a satellite must have in order to be in a geosynchronous orbit. (Please enter … 
astronomy
A geosynchronous satellite is a satellite whose orbital period matches the rotation of the Earth. Calculate the height above the surface of the Earth which a satellite must have in order to be in a geosynchronous orbit. (Please enter … 
math
The orbital velocity of a satellite is given by v=√GM/R+h, where G= 6.67*10^11 Nm^2kg^2, is the Universal Gravitational Constant, M=6*10^24 kg, is the mass of Earth, R=6.38*10^3 km, the orbit of the satellite, and h is artificial … 
math
The orbital velocity of a satellite is given by v=√GM/R+h, where G= 6.67*10^11 Nm^2kg^2, is the Universal Gravitational Constant, M=6*10^24 kg, is the mass of Earth, R=6.38*10^3 km, the orbit of the satellite, and h is artificial …