A runner dashes from the starting line (x=0) to a point 134 m away and then turns around and runs to a point 26 m away from the starting point in 16.8 seconds. To the nearest tenth of a m/s what is the average speed? and what is the velocity of the runner.
Average speed = (134+108)/16.8 m/s
Average velocity = 26/16.8 m/s
14,88
To find the average speed of the runner, we can use the formula:
Average speed = Total distance / Total time
Total distance = Distance covered while running away + Distance covered while running back
Total time = Time taken while running away + Time taken while running back
Distance covered while running away = 134 m
Distance covered while running back = 26 m
Total distance = 134 m + 26 m = 160 m
Time taken while running away = 16.8 seconds
Time taken while running back = 16.8 seconds
Total time = 16.8 seconds + 16.8 seconds = 33.6 seconds
Average speed = 160 m / 33.6 seconds
Now let's calculate the average speed:
Average speed ≈ 4.76 m/s (rounded to the nearest tenth)
To find the velocity of the runner, we need to consider both magnitude and direction. Velocity is a vector quantity, while speed is a scalar quantity. Since the runner runs away from the starting point and then comes back to it, the displacement is zero.
Therefore, the velocity of the runner is zero m/s. This means that the runner has a speed but no direction since they ended up at the same point where they started.