Find two mixed numbers so that the sum is 15 3/10 and the difference is 8 5/10

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Bobpursley just doesn't know the answer to b

To find two mixed numbers that satisfy the given conditions, let's start by assigning variables to represent the two numbers.

Let's call the first mixed number x and the second mixed number y.

According to the given conditions, we have two equations:

Equation 1: x + y = 15 3/10
Equation 2: x - y = 8 5/10

To solve this system of equations, we can use the method of substitution or elimination.

Let's start by using the substitution method. We can rearrange Equation 2 to get x = y + 8 5/10.

Now, substitute this expression for x in Equation 1:

(y + 8 5/10) + y = 15 3/10

Simplify the equation by adding the fractions separately from the whole numbers:

2y + 8 5/10 = 15 3/10

To eliminate the fractions, convert the mixed numbers to improper fractions:

2y + 8 1/2 = 15 1/3

Converting the mixed numbers to fractions:

2y + 17/2 = 46/3

To clear the fractions, multiply each term by the least common denominator (2*3=6):

6(2y + 17/2) = 6(46/3)

12y + 51 = 92

Now, isolate the variable y by moving the constant term to the other side of the equation:

12y = 92 - 51

12y = 41

Finally, divide by 12 to solve for y:

y = 41/12

To find the value of x, substitute this value of y back into Equation 2:

x - 41/12 = 8 5/10

Convert the whole number to a fraction with the same denominator as 12:

x - 41/12 = 8 1/2

Convert the mixed number to an improper fraction:

x - 41/12 = 17/2

To combine the whole numbers and fractions, convert 8 to an improper fraction:

x - 41/12 = 34/4

Simplify the equation by multiplying all terms by 12 to eliminate the fractions:

12x - 41 = (34/4) * 12

12x - 41 = 102

Add 41 to both sides of the equation to isolate x:

12x = 102 + 41

12x = 143

Divide by 12 to solve for x:

x = 143/12

Therefore, the two mixed numbers that satisfy the given conditions are x = 143/12 and y = 41/12.

A-B=8.5

A+B=10.333333

add the equations.

2A=18 8/10

A=9 4/10

now figure out B yourself