Please Help - Math

posted by Holly

107. Evaluate: logx 16 = -2

a. 0.25
b. 4
c. -4
d. -0.25

108. Evaluate: e2 ln 3

a. 6
b. 9
c. 12
d. 18

  1. Steve

    107. Solve
    log_x 16 = -2
    16 = x^-2
    16 = 1/x^2
    x = 1/4


    108.
    e^(2 ln 3)
    (e^ln 3)^2
    3^2
    9

  2. Holly

    thaanks ;3

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