A mechanic lifts the front of a car with a jack. Find the mechanical advantage if a force of 30.0 lb on the jack handle lifts the car that weighs 960 lb
M.A. = 960/30 = 32.
A direct drive winch with a handle radius of 12 in. and a drum radius of 3.0 in. is used to pull the end of a lever that is 8.0 ft long. The fulcrum is 6.0 ft from the end on which the winch is pulling. If a 240 lb load is attached to the short end of the lever, how much effort is required at the winch handle to lift the load?
To find the mechanical advantage, you need to divide the output force by the input force.
In this case, the output force is the weight of the car, which is 960 lb, and the input force is 30.0 lb.
Therefore, the mechanical advantage is calculated as:
Mechanical Advantage = Output Force / Input Force
Mechanical Advantage = 960 lb / 30.0 lb
Mechanical Advantage ≈ 32
So, the mechanical advantage of the jack in this scenario is approximately 32.
To find the mechanical advantage of the jack, we need to first understand the concept of mechanical advantage. Mechanical advantage (MA) is the ratio of the output force to the input force in a machine. In this case, the input force is the force applied on the jack handle, and the output force is the weight of the car being lifted.
Given that the force on the jack handle is 30.0 lb and the weight of the car is 960 lb, we can calculate the mechanical advantage using the formula:
MA = output force / input force
In this case, the output force is the weight of the car, which is 960 lb, and the input force is the force on the jack handle, which is 30.0 lb.
Let's plug in these values into the formula to find the mechanical advantage:
MA = 960 lb / 30.0 lb
MA = 32
The mechanical advantage of the jack in this case is 32. This means that for every 1 lb of force applied on the jack handle, it can lift or support 32 lbs of weight.