A wheel and axle arrangement has an axle with a diameter of 25cm. A rope is wrapped around the axle and is supporting a load of 2 tonnes.

1)If the mechanical advantage of the system is 30, determine the diameter of the wheel.
ANSWER = m
2)Determine the effort required to maintain the system equilibrium.
ANSWER = N

25 * 30 = 750 cm = 7.5 meters

2/30 = .067 tons or 133 pounds

To determine the diameter of the wheel in the wheel and axle arrangement and the effort required to maintain the system in equilibrium, we need to use the equation for mechanical advantage.

1) The mechanical advantage (MA) of a wheel and axle system is given by the ratio of the wheel diameter (Dw) to the axle diameter (Da). It can also be calculated as the ratio of the load (L) to the effort (E):
MA = Dw / Da = L / E

We are given the axle diameter (Da) as 25 cm and the mechanical advantage (MA) as 30. We need to determine the diameter of the wheel (Dw). Rearranging the equation, we have:
Dw = MA * Da

Substituting the given values:
Dw = 30 * 25 cm
Dw = 750 cm

Therefore, the diameter of the wheel is 750 cm.

2) The effort required to maintain the system in equilibrium (E) can be calculated using the equation:
E = L / MA

The given load (L) is 2 tonnes (2000 kg) and the mechanical advantage (MA) is 30. Substituting these values into the equation, we have:
E = 2000 kg / 30
E ≈ 66.67 kg

Therefore, the effort required to maintain the system in equilibrium is approximately 66.67 kg, or in units of force, 66.67 N.