Three wires are arranged in an equilateral triangle as shown in the figure below. The lower two wires are 4.00 apart. Assume all the wires are 1.35 long for this problem (extending into the screen).

To find the distance between the two upper wires, we can use the concept of trigonometry and the properties of an equilateral triangle.

Here's how you can calculate the distance between the two upper wires:

1. Draw a line from the center of the equilateral triangle to one of the upper wires. This line represents the altitude of the equilateral triangle.

2. Since the triangle is equilateral, the angle between the base and the altitude is 60 degrees (since all angles of an equilateral triangle are 60 degrees).

3. Now, we have a right triangle with one side being the altitude (1.35 units) and an angle of 60 degrees. We need to find the length of the base of this triangle, which represents the distance between the two upper wires.

4. Using trigonometry, we can use the sine function to find the length of the base of the triangle:
sin(60) = opposite / hypotenuse
sin(60) = x / 1.35

Rearranging the equation:
x = 1.35 * sin(60)

5. Now, calculate the value of x:
x = 1.35 * 0.866

6. The value of x is the distance between the two upper wires when the lower two wires are 4.00 apart. Calculate the value of x:
x ≈ 1.1654 units

Therefore, the distance between the two upper wires, when the lower two wires are 4.00 apart, is approximately 1.1654 units.

To better understand the problem, I would like to see the figure you mentioned. Please provide a description or a sketch of the figure so that I can proceed with the explanation.