A group of 30 people consists of 15 children, 10 men, and 5 women. Tom and Jerry are two of the men in the group. Five people are picked at random without replacement.
2A - Find the chance the first person picked is a man, given that the fourth and fifth people picked are children.
2B - Find the chance that more than two women are picked.
2C - Find the chance that Tom and Jerry both get picked.
cheating for final exam stat 2.2x eh? :D i want the answer too!!! :P
2b : .40189
A. If it is the first pick, it doesn't matter what the subsequent picks are, 10/30.
B. More than two women means 3, 4 or 5 women.
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
For 5 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 1/26 = ?
For 4 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 25/26 = ?
For 3 women, P = ?
Either-or probabilities are found by adding the individual probabilities.
C. P = 1/30 * 1/29 = ?
2B is 0.40189 is wrong
2C is also wrong.
2a is 10/28
2B : Hypergyometric: N=30, G=5, n=5, g>=3
Value: 2.193%
2C : Again Hypergeometry
2 Good items (Tom & Jerry).
So in 2C, N=30, G=2, n=5, g=2
Probability = 0.0299 = 0.023
2b .3571
2c ?
sorry 2a .3571
2b .0229 ?