A group of 30 people consists of 15 children, 10 men, and 5 women. Tom and Jerry are two of the men in the group. Five people are picked at random without replacement.

2A - Find the chance the first person picked is a man, given that the fourth and fifth people picked are children.

2B - Find the chance that more than two women are picked.

2C - Find the chance that Tom and Jerry both get picked.

cheating for final exam stat 2.2x eh? :D i want the answer too!!! :P

2b : .40189

A. If it is the first pick, it doesn't matter what the subsequent picks are, 10/30.

B. More than two women means 3, 4 or 5 women.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

For 5 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 1/26 = ?

For 4 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 25/26 = ?

For 3 women, P = ?

Either-or probabilities are found by adding the individual probabilities.

C. P = 1/30 * 1/29 = ?

2B is 0.40189 is wrong

2C is also wrong.

2a is 10/28

2B : Hypergyometric: N=30, G=5, n=5, g>=3

Value: 2.193%

2C : Again Hypergeometry

2 Good items (Tom & Jerry).

So in 2C, N=30, G=2, n=5, g=2
Probability = 0.0299 = 0.023

2b .3571

2c ?

sorry 2a .3571

2b .0229 ?