Algebra 2

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Find the exact solutions of x^2 - (y - 12)^2 = 144 and y = -x^2.

No solution?

  • Algebra 2 -

    second verse, same as the first:
    y = -x^2, so

    x^2 - (-x^2 - 12)^2 = 144
    x^2 - x^4 - 24x^2 - 144 = 144
    x^4 + 23x^2 + 288 = 0
    again, the discriminant is negative, so there are no solutions.

    x=0 works only in the 2nd equation
    (±12,12) only works in the first equation

  • Algebra 2 -

    Thank you!

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