Write the expression 13m^8 - 3m^4 + 4 in quadratic form if possible.
m^8?
how can you possibly think that those are the same?
Quadratic form means you want a quadratic expression of the form
az^2 + bz + c
Now, since m^8 = (m^4)^2, you have
13(m^4)^2 - 3(m^4) + 4
which is a quadratic if you let z=m^4. Then you have
13z^2-3z+4
Sorry, I'm very rusty on this concept. Thank you for the explanation.
To write the expression 13m^8 - 3m^4 + 4 in quadratic form, we can rewrite it as follows:
Let's substitute a variable, such as "x," for m^4.
Let x = m^4.
Now, we can rewrite the expression as:
13(x^2) - 3x + 4.
This is the expression in quadratic form, where the highest exponent is 2.
To write the expression 13m^8 - 3m^4 + 4 in quadratic form, we need to rearrange the terms so that we have a quadratic term followed by a linear term and a constant term.
First, let's rewrite the expression:
13m^8 - 3m^4 + 4
Next, we can break down the expression by factoring out the common factors:
m^4(13m^4 - 3) + 4
Now, we can see that we have a quadratic term (m^4), a linear term (-3), and a constant term (4). Therefore, we can say that the expression 13m^8 - 3m^4 + 4 cannot be written in quadratic form because it does not have a quadratic term.