physic
posted by Anonymous .
A car traveling at 80km/hr decelerates at 1.5m/s^2. Calculate
a) the time it takes to stop.
b) The distance travelled in the 3rd second.

a. Vf=Viat solve for t.
b. find distance at t=3, then distance at t=4 and subtract
d=vi+at where t=3, then do it for t=4 
convert 80km/hr to m/s first.

b)
d=vi+at
d=22.22+1.5+3=26.72
d=22.22+1.5+4=27.72
d=27.7226.72
d=1
is it correct for
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